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(Solved): 1. A Delta Ray (electron) In Water Receives A Maximum Energy Of 2.18 KeV From A Collision With A Pro ...


1. A delta ray (electron) in water receives a maximum energy of 2.18 keV from a collision with a proton. a) What is the energ


Table 7.1 Restricted Mass Stopping Power of Water, (-dE/pdx) A in MeV cm2 g 1, for Protons Energy (MeV) ( here).00 ev (cere),
1. A delta ray (electron) in water receives a maximum energy of 2.18 keV from a collision with a proton. a) What is the energy of the proton (use relativistic formula)? b) What is the unrestricted dE/dx of the proton in water (use Turner Table 7.1)? c) What restriction in keV (A) would you use to limit the delta ray energy to the width of of about 3 DNAs (R = 7.03 nm)? Determine the restricted energy loss (dE/dx)A using Turner Table 7.1? d) What fraction of the total energy transfer is given to delta electrons with kinetic energies up to A? Table 7.1 Restricted Mass Stopping Power of Water, (-dE/pdx) A in MeV cm2 g 1, for Protons Energy (MeV) ( here).00 ev (cere), kev () 0 keV ( nie) 910. 910. 910. 711. 910. 910. 910. 428. 0.05 0.10 0.50 1.00 10.0 100. 249. 146. 24.8 3.92 424. 238. 33.5 4.94 910. 428 270. 42.2 5.97 270. 45.9 7.28

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