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(Solved): For The Reactions Shown Below, We Added 4.25 ML Of 0.0450 M Na S To A Test Tube Containing One Of Th ...

For the reactions shown below, we added 4.25 mL of 0.0450 M Na S to a test tube containing one of the two cations (Cu2+ or Cd

For the reactions shown below, we added 4.25 mL of 0.0450 M Na S to a test tube containing one of the two cations (Cu2+ or Cd2+) and recovered 0.0183 g of precipitate. Cu(NO3)2(aq) + Na2S(aq) ? CuS(s) + 2 NaNO3(aq) Cd(NO3)2(aq) + Na2S(aq) ? CdS(s) + 2 NaNO3(aq) How much precipitate in moles would be recovered theoretically if the ion was Cu2+? (Enter an unrounded value. Use at least one more digit than given.) mol How much precipitate in moles would be recovered theoretically if the ion was Cd2+? (Enter an unrounded value. Use at least one more digit than given.) mol How much precipitate in grams would be recovered theoretically if the ion was Cu2+? 4.0 How much precipitate in grams would be recovered theoretically if the ion was Cd2+? Based on the precipitate amount recovered, which of the two ions was in the unknown? Cu2+ Cd2+

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