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(Solved): Given The Following Answer And Sensitivity Reports Cell $E$12 Objective Cell (Max) Name Profit Per B ...


Given the following answer and sensitivity reports Cell $E$12 Objective Cell (Max) Name profit per board Total Profit Origina
and 2 . The optimal profit is (1,2,37) is working at full capacity. The unused capacity of the first constraint is dollars #
Given the following answer and sensitivity reports Cell $E$12 Objective Cell (Max) Name profit per board Total Profit Original Value 0.00 Final Value $3,100.00 Original Value Final Value Cell $B$9 $C$ 9 $D$9 Variable Cells Name boards X 3 boards Y boards 2 Integer Contin Contin Contin $E$15 SE$16 $E$17 Constraints Name C elmacs time Lhs | Test stand time Lhs Graphic cards demand Lhs Cell Value Formula Status Slack 1033.333333SE$15<=$G$15 Not Binding 2566666667 SE$16<=$G$16 Binding 111110111 SE$17> SG$17 Not Binding 1191.666667 ISSO SCI 666667 Variable Cells Final Reduced Cost Objective Coefficient Value Allowable Increase 1 Cell $B$9 SC$9 SD$9 Name boards X boards Y boards Z Allowable | Decrease 1E+30 1E+30 258 3333333 Constraints | Cell Name $E$15 Celmacs time Lhs SE$16 Test stand time Lhs ISES17 Graphic cards demand Lhs Final ShadowConstraint Value Price R.H. Side 1033.3333330 3 600 1550 2 1 550 1291.666667 0 100 Allowable Increase I E+30 3850 1191.666667 Allowable Decrease 2566.666667 1430 1E+30 and 2 . The optimal profit is (1,2,37) is working at full capacity. The unused capacity of the first constraint is dollars # we add 10 units capacity to constraint 2 at a cost of $1.1 per unit, the amount of net benefit to the objective function is (Keep two decimal points if needed.

Expert Answer


Optimal Solutions are the final values i.e. X = 0, Y = 0, Z = 258.3333. Optimal Value is the final value = $ 3100. Constraint 2 is working at full capacity as s
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