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I Need Help On 4 And 5 Please. The Temperature Of A Saturated (cloudy) Air Parcel Is

I need help on 4 and 5 please.

the temperature of a saturated (cloudy) air parcel is

altitudes. 3) Air Density Changes with Altitude e standard atmosphere from sea level to an altitude of 5 km, the air density drops by kg per cubic m. per cubic m From 5 km to 10 km altitude, the air density drops by ce the thinning of air with altitude in the troposphere is most rapid at wers! 111kg per cubic m fround answers to nearest hundred 13 kg per cubic m Ithigh low) choose 1 p! Use Table 5.2 for this one. Be sure you're looking at the Density column. The question asks us ow much air density "drops". That means this is just a subtraction problem! So for the first part, sea- level is Okm, so the air density drop from Okm to Skm is 1.23 -0.74 0 . 4) Temperature Changes with Altitude - Sunny Day e temperature of an unsaturated (clearl air parcel is o "Cat sea level. If the air parcel ascends (eg, in e opdraft of a convection current) to an altitude of 1500 m with no change in phase of water vapor, the parcel will expand and cool to a temperature of "C Answer: -C (round answer to nearest whole number help! Use the dry adiabatic lapse rate for this one. That rate is 9.8 C per 1000 m (meaning the emperature goes down 9.8 C every 1000 m you go up in the atmosphere). So, if we go up 1500 m, try ng a proportion to tell me how many degrees the temperature will decrease. This particular problem Says at sea level the temperature is OC. If that's the case, what will the temperature be after it decreases at 1500 m? (The answer should be negative. Be sure to include negative signs when entering your answers in Blackboard.) 5) Temperature Changes with Altitude - Cloudy Day The temperature of a saturated (cloudy) air parcel is o c at an altitude of 2000 m. If the parcel ascends in the updraft of a thunderstorm to an altitude of 3500 m, the parcel will expand and cool to a temperature of about "C. Answer: *C (round answer to nearest whole number) Help: This problem is just like #4, but uses the moist adiabatic lapse rate, 6 °C per 1000 m.

4. Answer : -15degree Centigrade. Explanation :Dry adiabatic lapse rate = 9.8 degree Centigrade per 1000 m. Temperature of the parcel at sea level = 0 degree Celsius. The parcel rises upto a heigh