Nullspace. Let 14-15 -27 A= 1 4 0 3 5 (2 8 -1 8 3] (a) Use an Algorithm for Elimination to solve Az = 0. (The set of solutions to Ac = 0) is called the nullspace of A.) (b) The solutions you obtained in part (a) should depend on three parameters, say t?, t2, tz. For i = 1,2,3, find the vector ui obtained by assigning the parameter values ti = 1 and tj = 0 for j i . (c) Is S = {u}, U2, U3} a basis for the nullspace of A? Justify your answer.