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(Solved): Part A: What Mass Of Water Must Evaporate From The Skin Of A 69.0 Kg Man To Cool His Body 0.950 ?C ...

Part A:

What mass of water must evaporate from the skin of a 69.0 kg man to cool his body 0.950 ?C? The heat of vaporization of water at body temperature (37.0 ?C) is 2.42×106J/kg. The specific heat of a typical human body is 3480 J/(kg?K).

m=____________kg

Part B:

What volume of water must the man drink to replenish the evaporated water? Compare this result with the volume of a soft-drink can, which is 355 cm3

V=____________cm3

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