Two Rolls If we chose to pass the dice, then we would bank those points. If we chose to keep rolling, then in order to be successful we would need to roll no 1's twice. However, we would expect to get twice as many points IF we were to roll successfully. This would give us: Plsucess) - () 952 P(failure) = 1 - Value(success) = 16 Value(failure) = 0 (Round to four decimal What is the expected value for rolling twice? places) More Rolls As you can see, if we chose to roll even more times, then we could calculate the probabilities and values in a similar way. If we were to roll n times, then we have: / 25 P(success) = 25n P(failure) = 1 - Value (success) = 8.n Value(failure) = 0 What would the expected value be for: Three rolls? (Round to four decimal places) Four rolls? (Round to four decimal places) Five rolls? (Round to four decimal places) Strategy Having looked at the five different strategies, which would you choose? Roll once before passing Roll twice before passing Roll three times before passing Roll four times before passing Roll five times before passing Why would you choose this strategy? Edit Insert Formats - B IV x x A A > EEEEEE?N +